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2y^2-18y+81=261
We move all terms to the left:
2y^2-18y+81-(261)=0
We add all the numbers together, and all the variables
2y^2-18y-180=0
a = 2; b = -18; c = -180;
Δ = b2-4ac
Δ = -182-4·2·(-180)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-42}{2*2}=\frac{-24}{4} =-6 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+42}{2*2}=\frac{60}{4} =15 $
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